[Thor]

Here's a suggestion that seems to make sense (to me at least).

**Only when 2 gangs are at war**

If player A successfully defends against player B, xp earned is double the normal with the minimum being the maximum player A would earned for his level fighting a strong opponent.

I explain.
Example 1:
Player A is level 50 and the maximum he could earn by winning vs a tough opponent is 537 (I think it's the actual real amount here).

Player B of lvl x attacks him and lose.

Player A earns 325 xp
Twice that is over 537 so he earns 650 xp (325 X 2).

Example 2:
Player A is level 50 and the maximum he could earn by winning vs a tough opponent is 537 (I think it's the actual real amount here).

Player B of lvl x attacks him and lose.

Player A earns 214 xp
Twice that is under 537 so he earns 537 xp.

Again, I this should only work when at war but it would work for all attacks, leave, mug, hospitalize, berserk and gang battle. We could even make it triple for an hosp/berserk!!

Maybe it wont stop players from waking up to an event player x attacked you and lost and earn 78 xp here and there but it would at least make things more interesting when at war.